Question 91949
x^3 - 2x^2 + 3x - 4 is divided by x-3

multiply (x-3) by x^2 and substract it from x^3 - 2x^2 + 3x - 4 we get remainder as x^2 + 3x -4

now multiply (x-3) by x and substract it from x^2 + 3x -4 we get remainder as 6x -4

now multiply (x-3) by 6 and substract it from 6x -4 we get remainder as 14

so quotient will be x^2 + x +6 and remainder is 14