Question 1053007
Using the Distance Formula, determine the points X(-6,-4), Y(2,-2), and Z(0,5) form the vertices of a right triangle.
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Find the distances:
XY = sqrt(diffy^2 + diffx^2) = sqrt(2^2 + 8^2) = sqrt(68)
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Find YZ and XZ the same way.
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If the square of the longest side = the sum of the squares of the other 2, it's a right triangle.