Question 1052984
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Two trains leave towns 1084 km apart at the same time and travel toward each other. One train travels 19 kmh faster than the other. 
If they meet in 4 hours, what is the rate of each train?
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<U>Solution 1</U>.  One equation.


<pre>
Let x be the speed of the slower train, in km/h.
Then the speed of the faster train is (x+19).

The distance covered by the slower train in 4 hours is 4x.
The distance covered by the faster train in 4 hours is 4(x+19).

The equation is 

4x + 4*(x+19) = 1084.

Simplify and solve for x.
</pre>

<U>Solution 2</U>.  Two equations


<pre>
Let x be the speed of the slower train, in km/h, and
Let y be the speed of the faster train, in km/h.

Then you have this system of two linear equations

x + y = {{{1084/4}}},
x - y =   19.

Simplify

x + y = 271,
x - y =  19.

Add the two equations.

From this point please complete the solution on your own.
</pre>