Question 1052972
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Harry has $6.10 in his pocket. He has twice as many quarters as nickels and one more dime than quarters. 
How many of each coin does Harry have 
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For a moment, take off one dime from the collection (mentally).

Then you can group the remaining coins in the sets (1n, 2d, 2q) containing 1 nickel, 2 dimes and 2 quarters in each set.

The worth of each set is 5+2*10+2*25 = 75 cents.

The number of these groups is {{{(610-10)/75}}} = {{{600/75}}} = 8.

Thus there are 8 nickels, 16 dimes, and 16 quarters among remained coins.

So, the answer is:  8 nickels, 16+1 = 17 dimes, and 16 quarters in the original collection.
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