Question 1052858
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Hi  
Mean = $2,000, with a standard deviation of $400. n = 64
Construct a 95% confidence interval estimate of the mean daily income this parking garage generates. 
ME ={{{ z*sigma/sqrt(n)}}}
ME = 1.96*400/8
CI = 2000 ± 98
|
 = CI	z = value
90%	z =1.645
92%	z = 1.751
95%	z = 1.96
98%	z = 2.326
99%	z = 2.576