Question 1052870
Two lines that are perpendicular have a slope product that is the negative reciprocal, or -1.
y=(3/2)x-1 has a slope of 3/2
To find the negative reciprocal, flip the fraction and change the sign.  The negative reciprocal is -2/3
Now use the point slope formula where
y-y1=m(x-x1), where (x1,y1) is the point and m the slope
y-3=(-2/3)(x-2)
y-3=-(2/3)x+(4/3)
3 is 9/3
y=-(2/3)x+13/3 ANSWER
{{{graph(300,300,-10,10,-10,10,(-2x/3)+(13/3),(3x/2)-1)}}}