<PRE><B>Question 1052869</B>
Find the equation of the line that contains the point P(-2,0)
 and is perpendicular to the graph of y=2/3x-3
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The slope of y = (2/3)x-3 is 2/3
The slope of lines perpendicular is the negative inverse, -3/2
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Use {{{y - y[1] = m*(x - x[1])}}} where (x1,y1) is the point.

y-0 = (-3/2)*(x+2)
y = (-3/2)*(x+2)

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