Question 1052866
<pre>
 s,f,s,m,z,s,f,a,i,n

If the 3 s's and 2 f's looked different, maybe colored differently,
like this:

 <font color="red"><b>s</b></font>,<font color="brown"><b>f</b></font>,<font color="blue"><b>s</b></font>,m,z,<font color="green"><b>s</b></font>,<font color="orange"><b>f</b></font>,a,i,n

then the number of distinguishable "words" would be 10!.

However there are many arrangements that we cannot tell apart 
because the 3 s's and 2 f's look just alike.

So we must divide the 10! by the product of the factorials
of the numbers of indistinguishable letters.

Since there are 3 indistinguishable s's and 2 indistinguishable f's,
we divide the 10! by 3!2!:

Answer: {{{10!/(3!2!)}}}{{{""=""}}}{{{53628800/(6*2)}}}{{{53628800/12}}}{{{""=""}}}{{{302400}}}

Edwin</pre>