Question 91960
simplify the following question
(n^3-4n^2+3n-12) / (n^2-8n+16)
You can see the denominator factors as (n-4)^2
so use synthetic division to divide the numerator by n-4.
You will get the follow:

=[(n-4)(n^2+3)]/[(n-4)^2]
 
=[n^2+3]/[n-4]

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Cheers,
Stan H.