Question 1052737
{{{(33y-3y^2+6y^3+18)/(6y+3)=(6y^3-3y^2+33y+18)/(6y+3)=3(2y^3-y^2+11y+6)/(3(2y+1))=(2y^3-y^2+11y+6)/(2y+1)=(2y+1)(y^2-y+6)/(2y+1)}}}
For {{{y=-1/2}}} . the expression {{{(33y-3y^2+6y^3+18)/(6y+3)}}} is undefined, because the denominator is zero.
For {{{y<>-1/2}}} , the expression simplifies to {{{y^2-y+6}}} .