Question 1052740
The natural numbers are 1, 2, 3, ...
1. For all x there exist y such that (x < y) is TRUE,
because y=x+1 is a natural number, and x<x+1 means x<y.
2. There exist x for all y such that (x < y) is FALSE, because if Y=1, there is no natural number x such that x<1.
3. There exist x for some y such that (x < y) is TRUE, because for all natural numbers y except y=1, there is x=1, such that x<y.