Question 1052744
after leaving the runway, a plane's angle of ascent is 18 degrees and its speed is 278 feet per second. How many minutes will it take for the airplane to climb to a height of 13,000 feet? round answer to two decimal places.
:
Draw this out as right triangle where
 distance traveled by the plane is the hypotenuse,
 the side opposite 18 degrees is the height above the ground (13,000 ft)
:
let t = time in seconds
then
278t = distance traveled by the plane (hypotenuse) 
Use the sine of 18 degrees (side opposite/hypotenuse) 
sin(18) = {{{13000/278t}}}
.309 = {{{13000/278t}}}
.309(278t) = 13000
85.9t = 13000
t = {{{13000/85.9}}}
t = 151.33 seconds or 151.33/60 = 2.52 minutes