Question 1052703
 I need help finding the polynomial with the given zeros of 0, 8, and 1+sqrt2i with real coefficients please! I've tried and so far all I've gotten is x^2-8x-x+sqrt2i+8+sqrt2i 
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If the coefficients are to be Real, 1-sqrt(2)i must also be a zero
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Zeroes:: 0, 8, 1+sqrt(2)i, 1-sqrt(2)i
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f(x) = x(x-8)(x-(1+sqrt(2)i)(x-(1-sqrt(2)i)
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f(x) = x(x-8)((x-1)-sqrt(2)i)((x-1)+sqrt(2)i)
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f(x) = x(x-8)((x-1)^2 +2)
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f(x) = x(x-8)(x^2 -2x + 3)
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Cheers,
Stan H.