Question 1052691
The path of the object is a downward facing parabola. The object will reach its maximum height when dh(t)/dt = 0.
dh/dt = -32t + 48 = 0
This gives t = 1.5 seconds
The maximum height will be the value of the function at t = 1.5:
h(1.5) = 96 feet

The path of the object is given below:

{{{ graph( 400, 260, -1, 4, -10, 100, -16x^2+48x+60 )}}}