Question 1052680
{{{x=2}}} is a zero so {{{(x-2)}}} is a factor with an exponent of 1.
{{{x=1}}} is a zero so {{{(x-1)}}} is a factor with an exponent of 3.
{{{f(x)=1*(x-1)^3(x-2)}}}
{{{f(x)=(x-1)^3(x-2)}}}
Expanding,
{{{f(x)=x^4-5x^3+9x^2-7x+2}}}