Question 1052625
Calculate the slope of line XY.
First the slope,
{{{m[XY]=(6-3)/(7-6)=3/1=3}}}
Perpendicular lines have slopes that are negative reciprocals,
{{{m[XY]*m=-1}}}
{{{3*m=-1}}}
{{{m=-1/3}}}
Now use the point-slope form with point W.
{{{y-2=-(1/3)(x-2)}}}
{{{y-2=-(1/3)x+2/3}}}
{{{highlight(y=-(1/3)x+8/3)}}}