Question 1052631
1.{{{A+C=90}}}
2.{{{A+S=180}}}
3.{{{S=32+3C}}}
Substituting into eq. 2,
{{{A+32+3C=180}}}
{{{A+3C=148}}}
Subtract eq. 1 from this,
{{{A+3C-A-C=148-90}}}
{{{2C=58}}}
{{{C=29}}}
So then,
{{{A+29=90}}}
{{{A=61}}}
and
{{{61+S=180}}}
{{{S=119}}}