Question 1052572
If {{{ t = 9 }}} is the year 1999, then
{{{ t = 0 }}} is 1990 
You are given the points
( 9, 1.21 )
( 17, 1.46 )
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Use the general point-slope formula
{{{ ( C - 1.21 ) / ( t - 9 ) = ( 1.46 - 1.21 ) / ( 17 - 9 ) }}}
{{{ ( C - 1.21 ) / ( t - 9 ) = .25 / 8 }}}
{{{ ( C - 1.21 ) / ( t - 9 ) = 1 / 32 }}}
Multiply both sides by {{{ 32*( t-9 ) }}}
{{{ 32*( C - 1.21 ) = t - 9 }}}
{{{ 32C - 38.72  = t - 9 }}}
{{{ 32C = t + 29.72 }}}
{{{ C = (1/32)*t + .92875 }}}
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check the answer:
does the line go through ( 17, 1.46 )
{{{ C = (1/32)*t + .92875 }}}
{{{ 1.46 = (1/32)*17 + .92875 }}}
{{{ 1.46 = .53125 + .92875 }}}
{{{ 1.46 = 1.46 }}}
( you can check the other point )
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year = 2016
{{{ t = 26 }}}
{{{ C = (1/32)*t + .92875 }}}
{{{ C = (1/32)*26 + .92875 }}}
{{{ C = .8125 + .92875 }}}
{{{ C = 1.74125 }}}
Cash flow is $1.74
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check my math!