Question 1052491
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The length of a rectangle is 2 cm longer than its width. If the perimeter of the rectangle is 28 cm, find its area
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Let W = the width.
Then the length = W+2.


The perimeter is

2W + 2(W+2) = 28,

4W + 4 = 28  --->  4W = 28-4  --->  4W = 24  --->  W = {{{24/4}}} = 6.

<U>Answer</U>. The dimensions are 6 and 8. The area is 6*8 = 48 {{{cm^2}}}.
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