Question 1052409
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Rewrite the function f(x) = 2x^2- 8x + 9 in vertex form by completing the square.Also find the minimum value?
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<pre>
  {{{2x^2-8x +9}}} =    (if you are not familiar with the procedure "completing the square", 
                    then trace for each my step)


= {{{2*(x^2-4x + 4.5)}}} = {{{2*(x^2 - 4x + 4) + 1}}} = {{{2(x-2)^2 + 1}}}.


Completing the square is done.

The most right expression is a vertex form.

The minimum is achieved at x = 2.  The minimum value is 1.
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