Question 1052461
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If two planes flew between two cities at speeds of 200 mph and 260 mph respectively. 
If the slow plane required one half hours longer, how far apart of the cities 
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<pre>
200*(t+0.5) = 260*t,   (t = the time spent by the faster plane)


200t + 100 = 260t,


60t = 100,


t = {{{100/60}}} of an hour = 100 minutes.


The distance = {{{260*t}}} = {{{260*(100/60)}}}.


Use your calculator.
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