Question 1052352
{{{abs(x-2)<=7}}}



TWO CONDITIONS:
x-2 is non-negative;
x-2 is negative.
Solve for both conditions.



{{{x-2>=0}}}
-
{{{x-2<=7}}}
{{{x<=7+2}}}
{{{x<=9}}}



{{{x-2<0}}}
-
{{{abs(x-2)<=7}}}
{{{-(x-2)<=7}}}
{{{-x+2<=7}}}
{{{-x+2-7<=0}}}, just doing this way to avoid multiplying by negative value;
{{{-x-5<=0}}}
{{{-5<=x}}}



Both conditions to be true
{{{highlight(-5<=x<=9)}}}


[-5,9]