Question 1052341
Right now, you have 10 qts. of fluid, of which 10% is anti-freeze. Let n be the amount of pure anti-freeze to be added. Then:
.1(10)-.1n+n=.25(10)
1+.9n=2.5
.9n=1.5
n=1.67 qts. need to be replaced with pure anti-freeze to achieve the desired mix. &#9786;&#9786;&#9786;&#9786;