Question 1052359
 (3,7), 
(5,-1) Midpoint(4, 3) Midpoint Pt(x,y):  ( {{{(x[1] + x[2])/2}}}, {{{(y[1] + y[2])/2  )}}})
D = {{{ sqrt ( (x[1]-x[2])^2+ (y[1]-y[2])^2 ) }}}
Diameter = sqrt(4 + 64) = sqrt(68) = 2sqrt(17)
radius = sqrt(17)
circle
(x-4)^2 + (y-3)^2 = r^2
(x-4)^2 + (y-3)^2 = 17

{{{drawing(300,300,    -10,10,-10,10,  
 grid(1),
circle(3,7,0.4),
circle(5,-1,0.4),
circle(4,3,sqrt(17)),
circle(4,3,0.4),
graph( 300, 300, -10,10,-10,10,0))}}}