Question 1052251
An airplane takes off from an airport at 7:00 a.m. traveling at a rate of 350 mph. Two hours later, a jet takes off from the same airport following the same flight path at 490 mph. How many hours will it take the jet to catch up with airplane?
<pre>Let time taken by jet to get to meetup point, be T
Then time taken by airplane to get to meetup point = T + 2
We then get the following DISTANCE equation: 490T = 350(T + 2)
Solve this for T, the time the jet took to catch up with the airplane. You should get: {{{highlight_green(matrix(1,2, 5, hours))}}}
It's that simple.....nothing complex!