Question 91339
basically this is a solving equation problem

{{{3x^3+ x^2-3x-1 = 0}}}

I am going to solve it by factoring.

{{{x^2(3x + 1)-(3x + 1) = 0}}}

{{{(3x + 1)(x^2-1) = 0}}}

{{{(3x + 1)(x + 1)(x - 1) = 0}}}

so 3x + 1 = 0  ===>  {{{x = -1/3}}}

x + 1 = 0  ====>  x = -1

x - 1 = 0  =====> x = 1

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