<PRE><B>Question 1052180</B>
The sum of three consecutive even integers is 48 less than twice the smallest of the three integers find the integers 
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1st:: x-1
2nd:: x
3rd:: x+1
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Equation:
sum = 2(x-1) - 48
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3x = 2x-2 - 48
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x = -50
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1st: x-1 = -51
2nd: x = -50
3rd: x+1 = -49
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Cheers,
Stan H.
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