Question 1052165
Start with a generic equation,
{{{ax+by=1}}}
So when, {{{x=0}}}, {{{y=2}}},
{{{a(0)+b(2)=1}}}
{{{b=1/2}}}
and
when {{{y=0}}}, {{{x=7}}}
{{{a(7)+b(0)=1}}}
{{{a=1/7}}}
So then,
{{{x/7+b/2=1}}}
{{{2x+7y=14}}}
or any multiple of that equation,
{{{(2*alpha)x+(7*alpha)y=14*alpha}}}
where {{{alpha}}} is any non-zero real number.