Question 1052151

let x-2,x,x+2 be the odd consecutive integers.
{{{3(x-2)}}}+{{{2(x)}}}={{{2(x+2)}}}+{{{(5)}}}

{{{(3x-6)}}}+{{{(2x)}}}={{{(2x+4)}}}+{{{(5)}}}

{{{(3x-6)}}}={{{(4)}}}+{{{(5)}}}
{{{(3x)}}}={{{(10)}}}+{{{(5)}}}
{{{(x)}}}={{{(15/3)}}}
{{{(x)}}}={{{(5)}}}

the numbers are 3,5,7
check

3(3)+2(5)=5+14
19=19