Question 1052103
The equation looks like it comes from consecutive odd integers.  Three times the first odd integer is five more than two times the next odd integer.  Find n and you can evaluate the two integers.


{{{3(2n+1)=2(2n+3)+5}}}
{{{6n+3=4n+6+5}}}, distributive property;
{{{6n+3=4n+11}}}
{{{6n+3-4n=4n+11-4n}}}, maybe a step you should have seen to do but did not;
{{{6n-4n+3=4n-4n+11}}}
{{{2n+3=11}}}
{{{2n=11-3}}}
{{{2n=8}}}
{{{highlight(n=4)}}}


The numbers are 9 and 11.