Question 1052089
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Systems  of  equations  in  three  variables  HELP!!
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a + b      =  3    (1)
  - b +  c =  3    (2)
a +     2c = 10    (3)

Add equations (1) and (2) (both sides). You will get

a + c = 6.         (4)

Distract equation (4) from the equation (3). You will get

c = 10-6 = 4.

So, you just found the solution for c:  c=4.

Substitute c=4 into equation (2). You will get

-b + 4 = 3.

Hence, b = 4-3 = 1.

Substitute b=1 into equation (1). You will get

a + 1 = 3.

Hence, a = 3-1 = 2.

<U>Answer</U>.  a=2, b=1, c=4.
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