Question 1051994
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Three computer viruses arrived as an e-mail attachment. Virus A damages the system
with probability 0.4. Independently of it, virus B damages the system with probability 0.5.
Independently of A and B, virus C damages the system with probability 0.2. What is the
probability that the system gets damaged?
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1 - (1-0.4)*(1-0.5)*(1-0.2) = 1 - 0.6*0.5*0.8 = 1 - 0.24 = 0.76.