Question 1051974
square root ( (x-4) * (x+5) ) =
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( (x-4) * (x+5) )^(1/2) =
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(x-4)^(1/2) * (x+5)^(1/2)
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assuming x > 0, roots are x = 4 and x = -5
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note that for -5 < x < 5 the function values are imaginary and the domain is x < or = -5 and x > or = 4, range is all real numbers > or = 0 
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here is a graph of the function
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{{{ graph( 300, 200, -15, 15, -5, 13, sqrt(x^2+x-20)) }}}
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