Question 1051957
log(x + 5) + 2 log x
= log(x+5) + log(x) + log(x)
Adding logs --> multiply
= log(x*x*(x+5))
= log(x^2*(x+5)) or log(x^3+5x)
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3 log2t - 1/3 log2u + 4 log2v
Is 2 the base?
or is it 3log(2t) ?
Use parentheses.
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Even better, use the rendering on the site, {{{ and }}}
--> {{{3log(2,t)}}}
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Click the "Show source" in the upper right to show the formatting.