Question 1051844

Find log0.048 if log2=0.3010 log3=0.4771 and log5=0.6990
<pre>log 2 = 0.301		log 3 = .4771
{{{log 0.048 =  log (48/"1,000") = log (48) - log ("1,000")}}} =====> {{{log (2^4 * 3) - log (10^3)}}} ====> {{{log (2^4) + log (3) - 3 log (10)}}} ======> {{{4 log (2) + log (3) - 3}}}
4(.301) + .4771 – 3 = 1.204 + .4771 – 3, or {{{highlight_green(- 1.3189)}}}