Question 1051841
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Find the equation of the circle which passes through the origin and cuts off intercepts 3 and 4 from the positive parts of the axes respectively.
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There are two such circles and, correspondingly, two equations.


The first circle has the center at (1.5,2) and the radius {{{sqrt(1.5^2 + 2^2)}}} = {{{sqrt(2.25 + 4)}}} = {{{sqrt(6.25)}}} = 2.5:

{{{(x-1.5)^2 + (y-2)^2}}} = 6.25.


The second circle has the center at (2,1.5) and the same radius:

{{{(x-2)^2 + (y-1.5)^2}}} = 6.25.
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