Question 1051834
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What you ask cannot be done.  You have two equations and three variables, namely X, x, and y.  X and x are not now, never have been, and never will be the same thing.


However, going on the assumption that you were just being sloppy and actually meant:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ 7y\ =\ 31]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ +\ 3y\ =\ 7]


Solve the first equation for *[tex \Large x]:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x\ =\ -7y\ +\ 31]


Substitute the RHS expression in place of *[tex \Large x] in the second equation and then solve for *[tex \Large y]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2(-7y\ +\ 31)\ +\ 3y\ =\ 7]


... and then solve for *[tex \Large y].   Once you know *[tex \Large y], substitute that value back into either original equation and solve for *[tex \Large x].


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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