Question 1051773
If -1 is a 0, then x+1 is the binomial, because x=1=0, and x=-1
=======x^2
x-1/x^3+0x^2+0x+9
====x^3-x^2
change signs and subtract
======-x
x-1/-x^2+0x+9
====-x^2+x
change signs and subtract
=====-x +9
x-1 does not divide evenly into -x+9, so -1 is not a 0.
f(-1)=-1+9=8, which is not 0.
graph confirms that:{{{graph(300,300,-10,10,-10,10,x^3+9)}}}
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