<PRE><B>Question 1051630</B>
exactly 5 is 88C5(0.4)^5*0.6^83=1.5 X 10^(-13) or essentially 0.
4,3,2,1 will also be 0.
Therefore, c is 0.
b is 1.0
The expected value for 88 households is 88*0.4 or 35.2
The variation is 35.2*0.6 (np(1-p))=21.12, and the standard deviation is 4.6
5 households is 30.2/4.6, or 6.5 standard deviations below the mean.
Could the question be 8 households?
There the probability of 5 would be 8C50.4^5*0.6^3=0.124
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