Question 1051454
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Jack is 4 times as old as Lacy.<pre>J = 4L</pre>10 years ago...<pre>10 years ago Jack was J-10
10 years ago Lacy was L-10</pre>...the sum of their ages was 40.<pre>J-10 + L-10 = 40 

Simplify that and substitute 4L for J,
then solve the equation for L. That will be
Lacy's age. Then Substitute what you get for 
L in J = 4L to find Jack's age.

Edwin</pre>