Question 1051498
bean A is 0.08/pound
bean B is 0.32/pound
A+B=110
.08A+0.32(B)=29.7 (that comes from the mixture of 110 pounds at 0.27/pound)
A=110-B
0.08(110-B)+0.32B=29.7
8.8-0.08B+0.32B=29.7
0.24B=20.9
B=87.1 pounds@0.32=27.87
A=22.9 pounds@0.08=1.83
That is 110 pounds with a dollar value of $29.70, which is $0.27 per pound.
This is reasonable if one can weigh beans to the nearest tenth of a pound.