Question 91842
Let the distance be X miles and the speed of the car on the forward journey be y mph. Hence time taken= x/y hours. On the return journey, the speed is increased by 7 mph, hence new speed is y+7 mph. Hence time taken = x/(y+7) hrs= 6 hrs
 from the 1st eq, we get x=7y: from the second we get x= 6y+42: hence 6y+42=7y
hence y=42. subsituring the value of y in eq 1, we get x(distance)=294 miles