Question 1051420
log3(x+12)+log3(x-12)=4
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If you mean {{{log(3,(x+12)) + log(3,(x-12)) = 4}}}
{{{log(3,(x+12)*(x-12)) = 4 = log(3,3^4)}}}
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x^2 - 144 = 81
x^2 = 225
x = 15
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x = -15 is rejected since log(-15-12) is the log of a negative number.
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If you had mentioned that 3 was the base, someone might have done the problem sooner.