Question 1051461
find the bone density scores that can be used as cutoff values seperating the most extreme 1% of all scores
test scores normally distributed, mean of 0, standard deviation of 1 
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Lower limit:: z = invNorm(0.01) = -2.5758
Upper limit:: z = invNorm(0.99) = 2.5758
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Cheers,
Stan H.
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