Question 1051312
use{{{ y=a*sqrt(bx-h) +k}}}

 Given {{{b= -1}}} and {{{h=1}}}, since  the parent function is {{{y= sqrt( x) }}}->{{{a=1}}} and {{{k=0}}}

so, you have 

{{{ y= sqrt(b(x-h)) }}}

{{{ y= sqrt(-1(x-1)) }}}

{{{ y= sqrt(-x+1) }}}