Question 91796
according to the problem:

assume the two factors are x and y

then x + y = 11
     x*y = 28

a quadratic equation can be formed:

from the first equation y = 11 - x
substitute y: 

{{{x*(11 - x)= 28}}}

{{{11x - x^2 = 28}}}

or {{{x^2 - 11x +28 = 0}}}

solve this equation: (x -4)(x - 7) = 0

so x =  4 and x = 7
the corresponding y values are y =7 and y = 4.

The answer the two factors are 4 and 7.