Question 1051287
{{{(2ab-6a)/(9a-3ab )}}}


{{{2a(b-3)/3a(3-b )}}}


{{{2cross(a)(b-3)/3cross(a)(3-b )}}}


{{{2(b-3)/3(3-b )}}}.......since {{{2(b-3)=-2(3-b)}}}, we have


{{{-2(3-b)/3(3-b )}}}


{{{-2cross((3-b))/3cross((3-b) )}}}


{{{-2/3}}}