Question 91821
{{{f(x) = x^2}}} and {{{f(x) = x + 1}}}
{{{f(x) = f(x)}}}
{{{x^2 = x + 1}}}
{{{x^2 - x - 1 = 0}}}
Solve anyway you know of:
{{{x^2 - x = 1}}}
{{{(x - 1/2)^2 = 5/4}}}
{{{x = (1 +- sqrt(5))/2}}}