Question 1051156
Evaluating for what value of x?


{{{f(x)=3x^2-5x+17}}}, given function.



Difference Quotient in general,  {{{(f(x+h)-f(x))/h}}}, and examine this quotient as h tends toward 0.



YOUR difference quotient should be found to be  {{{6x-5}}}.


I left-out the steps.
You need to substitute the needed expression, {{{f(x+h)=3(x+h)^2-5(x+h)+17}}}, but simplify it before putting it into its role in the difference quotient formula.