Question 1051118

Jack is 3 times as old as Lacy. 8 years from now the sum of their ages will be 60. How old are they now?

let Jack’s age be {{{x}}} 
if Jack is {{{3}}} times as old as Lacy, then Lacy is {{{x/3}}}
8 years from now Jack’s age will be {{{x+8}}} and Lacy will be {{{x/3+8}}}
if the sum of their ages will be {{{60}}}, then we have
{{{(x+8)+(x/3+8)=60}}} 
{{{x+8+x/3+8=60}}} 
{{{x+x/3+16=60}}} 
{{{3x/3+x/3=60-16}}} 
{{{4x/3=44}}} 
{{{4x=44*3}}} 
{{{x=(44*3)/4}}}
{{{x=(11*3)/1}}}
{{{x=33}}}-> Jack’s age

 then Lacy is {{{x/3}}}->{{{33/3}}}->{{{11}}}->Lacy’s age



Cary is 4 years older than Dan. In 5 years the sum of their ages will be 72. Find the age of each man now. 

let Cary’s age be {{{x}}}
if Cary is {{{4}}} years older than Dan, Dan’s age is {{{x-4}}}

 In {{{5 }}} years will be Cary  {{{x+5}}} and Dan will be {{{x-4+5=x+1}}}

if the sum of their ages will be {{{72}}}, we have

{{{(x+5)+(x+1)=72}}} 
{{{x+5+x+1=72}}} 
{{{2x+6=72}}} 
{{{2x=72-6}}} 
{{{2x=66}}} 

{{{x=33}}} ->Cary’s age
Dan’s age is {{{x-4=29}}}